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x^2-132x-2059.14=0
a = 1; b = -132; c = -2059.14;
Δ = b2-4ac
Δ = -1322-4·1·(-2059.14)
Δ = 25660.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-\sqrt{25660.56}}{2*1}=\frac{132-\sqrt{25660.56}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+\sqrt{25660.56}}{2*1}=\frac{132+\sqrt{25660.56}}{2} $
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